Re: A is dense in S
- From: Tonico <Tonicopm@xxxxxxxxx>
- Date: Tue, 21 Aug 2007 01:16:34 -0700
On Aug 20, 5:22 pm, Kiuhnm <kiuhnm03.4t.yahoo.it> wrote:
There is something I don't quite understand about "denseness".****************************************************
For instance, I have two very similar definition:
1) A subset A of S is called dense in S if cl(A) = S, and is called
nowhere dense if S\cl(A) is dense in S.
2) A subset A of S is called dense in S if cl(A) > S. Moreover, A is
somewhere dense in S iff there exists an open U < S such that cl(A/\U) > U.
I'm also trying to prove that A is somewhere dense in S (in the sense of
2) iff int(cl(A))<>0. It's clear that if A is s.d. then int(cl(A))<>0,
but what about the converse?
Kiuhnm
You may be interested in the next equivalent definition of dense set
which, imo, is easier to grasp and way easier to work with in many
cases:
A subset A of a top. space X is dense (in X) iff for every open set U
in X, the intersection of A with U is non empty <==> the above is true
when U belongs to some basis of the topology on X.
Regards
Tonio
.
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