Re: quasi-cyclotomic polynomials



On Fri, 24 Aug 2007 19:35:49 -0400, quasi
<quasi@xxxxxxxx> wrote:

For this discussion, all polynomials will be elements of Z[x].

Call a polynomial "quasi-cyclotomic" if all of its roots have complex
modulus equal to 1.

[...]

Question (1):

Does there exist a nonconstant, primitive, quasi-cyclotomic polynomial
whose leading coefficient is not 1 or -1?

Note -- by primitive, we mean that the coefficients have no common
factor (in Z).

Question (2):

Does there exist a nonconstant, monic, irreducible quasi-cyclotomic
polynomial which is not cyclotomic?

Note -- if the answer to question (2) is "no", then the answer to
question (1) is automatically also "no".

I don't know anything about this myself, but apparently
there's a theorem of Kronecker which says that all the
roots of a quasi-cyclotomic polynomial are roots of unity:

<http://www.groupsrv.com/science/about89561.html>

Hence, the polynomial divides x^n - 1, for some n; this is
a product of cyclotomic polynomials, which are irreducible;
hence it is itself cyclotomic; so the answer to (2) is "no"
(unless I've boobed as usual).
--
Angus Rodgers
(twirlip@ eats spam; reply to angusrod@)
Contains mild peril
.



Relevant Pages

  • Re: JSH: Keep it simple
    ... arbitrary rule that you take roots of monic polynomials with integer coefficients. ... integral root is divisible by something that is coprime to ... Your claim regarding rational roots of this polynomial cannot do that, since the standard theory makes no claims regarding common factors among such roots. ...
    (sci.math)
  • Re: Orthogonal polynomials (was Chebyshv, etc.)
    ... Legendre, Chebyshev, Hermite, etc.) have n real roots in the ... This general property of orthogonal polynomials is proved as ... you can simply ignore any zeros ... If alpha is a real root of phi_k, ...
    (sci.math)
  • Re: New paper, algebraic integers, Galois Theory
    ... > Now consider the case that m, f, and u are algebraic integers, then I ... > something about the factors of roots of monic polynomials with integer ... Note that this claim does not require Galois Theory, ...
    (sci.math)
  • Re: Question on algebraic numbers
    ... adjoining to Q the roots of all polynomials over Q. ... extensions of Q which have a solvable Galois group. ... solutions by radicals). ...
    (sci.math)
  • Re: Some math, algebraic integers
    ... >> Like, yeah, the polynomial has rational roots, which is what I already ... are mathematicians as a group as big about their ... > be related to the coefficients of their irreducible polynomials. ... So I said, hey, it all follows in the ring of algebraic integers too! ...
    (sci.math)