Re: The dimension of fixed space of a matrix
- From: Robert Israel <israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Sun, 26 Aug 2007 00:57:04 -0500
Gvnaena Pura <tianran.chen@xxxxxxxxx> writes:
I'm wondering if there is an easy way for knowing the dimension of the
fixed subspace of a matrix, when it act on a vector space. Here, by
the fixed subspace, what I mean is the subspace W such that Mx = x for
all x in W where M is the matrix in question. It is also the kernel
of the map (I-M), where I is the identity. (maybe there is a formal
for this, but I don't know). Thanks in advance.
So if M is n x n, you want n - rank(M-I). To actually find it numerically,
use Gaussian elimination or singular value decomposition.
--
Robert Israel israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.
- Follow-Ups:
- Re: The dimension of fixed space of a matrix
- From: Gvnaena Pura
- Re: The dimension of fixed space of a matrix
- References:
- The dimension of fixed space of a matrix
- From: Gvnaena Pura
- The dimension of fixed space of a matrix
- Prev by Date: Re: Another Inconvenient Truth
- Next by Date: Re: ? eigenvalus of generalized e-problem
- Previous by thread: The dimension of fixed space of a matrix
- Next by thread: Re: The dimension of fixed space of a matrix
- Index(es):
Relevant Pages
|