Re: Peerless Pair Postulate.By Aiya-Oba

On Thu, 30 Aug 2007, Anthony A. Aiya-Oba wrote:

"Other than two, there are no natural numbers whose sum of their pairs,
equal their squares."

Thus, (n + n) = n^2, if, and only if; ( n = 2)

n + n = n^2
2n = n^2
n^2 - 2n = 0
n(n - 2) = 0
n = 0 or n = 2

How dare you claim 0 is unnatural!
.

References:
- Peerless Pair Postulate.By Aiya-Oba
  - From: Anthony A. Aiya-Oba

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