Re: polar equation to rectangular form

On Sep 2, 8:57 pm, conrad <con...@xxxxxxxxxx> wrote:
I have the polar equation:
r = 5*sin t
and in rectangular form it is:
x^2 + y^2 = 5*y

My graphing tool is kind
of limited and accepts an
inequation in one variable.

I'm trying to graph it as
such, so that the rectangular
form in one variable will
produce the same graph as
r = 5*sin t

so by solving for x
I got:
sqrt(y*(5 - y))


Now change axes and plot both x graphs as a function of y:
x = +/- sqrt(y*(5 - y)). But the procedure gets tough with
difficult examples like say r = cos(4 t) + 3 t.


.

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