Re: rings with finitely many principal ideals
- From: Brian VanPelt <brvanpelt@xxxxxxxxxxxxx>
- Date: Sun, 02 Sep 2007 23:32:41 -0400
On Sun, 02 Sep 2007 20:59:09 -0400, quasi <quasi@xxxxxxxx> wrote:
On Sun, 02 Sep 2007 22:18:19 +0200, Jannick Asmus
<jannick.news@xxxxxx> wrote:
On 02.09.2007 22:08, Jack Schmidt wrote:
On Sep 2, 3:35 pm, quasi <qu...@xxxxxxxx> wrote:
Does there exist a ring R with only finitely many principal ideals but
infinitely many ideals?
quasi
An ideal is the sum of the principal ideals contained within it.
Thus a ring with finitely many principal ideals is both Noetherian and
Artinian, hence the ring is 0-dimensional and is the finite product of
local Artinian rings.
So must a local Artinian ring with finitely many principal ideals have
finitely many ideals?
quasi
Whoah, I don't think locality is important for this answer. Let's go
back to modules over a ring for a second. A ring R is (left, right or
both) Aritinian if it has the same property as a (left, right or both)
R-module.
Now, an R-module is Aritnian if it obeys the Descending Chain
Condition - every descending chain of submodules stabilizes. Ideals
are submodules of the ring viewed as a module over itself. So, the
language of modules is appropriate here with the added benefit of
being more general.
Let A be a left, Artinian module over a ring R, and suppose A_1, A_2,
.... are a collection of submodules - I'm not saying they are all
dstinct from each other because that would be giving too much away.
Then, what do you make of
A_1 intersect A_2
A_1 intersect A_2 intersect A_3
A_1 intersect A_2 intersect A_3 intersect A_4
etc?
If you wan't, substitute the word ideal for module everywhere to
achieve your desired result.
Thanks,
Brian
.
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