Re: minimum of a function into two variables
- From: David W. Cantrell <DWCantrell@xxxxxxxxxxx>
- Date: 03 Sep 2007 17:39:53 GMT
Andrea <acirulli@xxxxxxxxx> wrote:
Hi,
I need some suggestion,
Let P_s=p!/{n choose p}
I assume that your n and p are positive integers; let us know if that is
not the case.
I need to calculate fixing P_s (for example P_s=2^-12) the minimum of
this function:
f(x)=p+ p \times \log{n}
I don't suppose you meant f(x), since x hasn't been mentioned elsewhere;
rather, you wish to minimize p(1 + log(n)). Is that correct?
You say that P_s is fixed and give P_s = 2^-12 as an example. But,
assuming that n and p are positive integers, I suspect it not possible to
have P_s = 2^-12 exactly. Are we to assume that your example was not a good
one and that, in reality, your fixed P_s will always be one which can be
obtained exactly using positive integers for p and n?
David W. Cantrell
.
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