Re: minimum of a function into two variables

David W. Cantrell <DWCantrell@xxxxxxxxxxx> writes:

Andrea <acirulli@xxxxxxxxx> wrote:
Hi,
I need some suggestion,
Let P_s=p!/{n choose p}

I assume that your n and p are positive integers; let us know if that is
not the case.

I need to calculate fixing P_s (for example P_s=2^-12) the minimum of
this function:
f(x)=p+ p \times \log{n}

I don't suppose you meant f(x), since x hasn't been mentioned elsewhere;
rather, you wish to minimize p(1 + log(n)). Is that correct?

You say that P_s is fixed and give P_s = 2^-12 as an example. But,
assuming that n and p are positive integers, I suspect it not possible to
have P_s = 2^-12 exactly.

You could take n = 2^12 and p = 1.
--
Robert Israel israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.

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