Re: Derivative of multivariable function
- From: Jannick Asmus <jannick.news@xxxxxx>
- Date: Tue, 04 Sep 2007 10:58:23 +0200
On 04.09.2007 07:03, Jennis.kr@xxxxxxxxx wrote:
Hi,
I little bit stuck to solve those derivatives of the integrals.
the question is :
to find f' when g:R->R continuous.
1. f(x,y)=intgeral from a to x+y of g
2. f(x,y)=integral from a to (x multiply y) of g
3. f(x,y,z)=integral from (base x with exponent y) to [sin(x sin(y sin
z))] of g.
I would be grateful if you can help me .
Thanks.
Hint: Let G(z)= integral from a to z of g. Then what is G'? Thus the function in the first problem reads f(x,y) = G(x+y) ...
HTH.
J.
.
- Follow-Ups:
- Re: Derivative of multivariable function
- From: tomas778899
- Re: Derivative of multivariable function
- References:
- Derivative of multivariable function
- From: Jennis . kr
- Derivative of multivariable function
- Prev by Date: Re: Engineering Fluid Mechanics 8th Ed. by Crowe
- Next by Date: Re: JSH: What is surrogate factoring? Once more.
- Previous by thread: Re: Derivative of multivariable function
- Next by thread: Re: Derivative of multivariable function
- Index(es):
Relevant Pages
|
