Re: TOPOLOGY: Compactness and T2 - fix
- From: "Francisco" <francisco.bravo.diez@xxxxxxxxxxxxxxx>
- Date: Sun, 9 Sep 2007 19:05:25 +0200
"quasi" <quasi@xxxxxxxx> escribió en el mensaje
news:b048e3der04oon4hmcrbsqm7p3df7vu9ul@xxxxxxxxxx
On Sun, 9 Sep 2007 16:32:20 +0200, "Francisco"
<francisco.bravo.diez@xxxxxxxxxxxxxxx> wrote:
Let (X,T) be a compact, T2 (Hausdorff) topological space,
having a single non-isolated point x_0. Let U be a subset
of X with x_0 in U.
Prove that U is an open <=> X-U is finite.
Hints for the => direction:
(1) Suppose U is open.
(2) Let x be an element of X-U. Then {x} is open. Explain.
(3) Cover X using U as well as all the singletons from X-U.
Does this implication need the T2 premise?
As far as I can see, the => implication doesn't need T2. In fact, even
the <= implication doesn't need it -- T1 would suffice.
Thanks for your help, but I can't figure out why X\U finite, X compact,
X T1 => X\U closed. Would you please elaborate on that? (sorry
about my ignorance).
Hints for the <= direction:
(1) Suppose X-U is finite.
(2) Then X-U is closed. Explain.
For the <= direction, compactness is irrelevant.
For which type of space is a singleton always closed?
For T2. OK, I see it pretty clear now. Many thanks for the illustration ;)
Francisco
.
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