Re: Convex Functions



quasi wrote:

On Sat, 08 Sep 2007 18:23:00 EDT, Maury Barbato
<mauriziobarbato@xxxxxxxx> wrote:


Remembering that a function f:R^n->R is said
to be increasing if for every x, y in R^n, with
x_i >= y_i for every i in {1,...,n}, we have
f(x)>=f(y), we could have the following

Let f:R^n->R be an increasing function such that
for every x,y in R^n we have

f((x+y)/2)<=[f(x)+f(y)]/2.

then f is convex.

But it seems quite hard to prove or disprove this
statement.

Ok, here's a proof -- I think this one actually works
...

I plan to prove that f is continuous. Since f is
midpoint-convex,
continuity of f would suffice to imply that f is
convex.

Let p be a point of R^n.

Denote the i'th coordinate of p by p[i]. Thus, p =
(p[1], ..., p[n]).

For any nonzero vector v in R^n with nonnegative
entries, let L(p,v)
be the line through p, parallel to v.

Restricted to L(p,v), f is midpoint-convex and weakly
increasing,
hence f is continuous on L(p,v).

Let u be the unit vector in the direction of <1, ...,
1>. Then f is
continuous on L(p,u).

Let p_1, p_2, p_3, ... be an arbitrary sequence of
points approaching
p. To show that f is continuous at p, it suffices to
show that the
sequence

f(p_1), f(p_2), f(p_3), ...

approaches f(p).

Define a sequence of nonnegative reals c_1, c_2, c_3,
... by

c_m = max( abs(p_m[i] - p[i]), i = 1, ..., n )

Since p_1, p_2, p_3, ... converges to p, it follows
that c_1, c_2,
c_3, ... converges to 0 (from above).

Since f is (weakly) increasing on R^n,

f(p - c_m*u) <= f(p_m) <= f(p + c_m*u)

Letting m approach infinity, continuity of f on
L(p,u) implies

f(p - c_m*u) approaches f(p)

and

f(p + c_m*u) approaches f(p)

Thus, by the squeeze theorem, as m approaches
infinity, f(p_m)
approaches f(p).

Therefore f is continuous at p. Hence, since p was
arbitrary, f is
continuous on R^n, as claimed.

It follows that f is convex.

quasi

Very very good work, quasi!! A simple, elegant proof!
Thank you a lot for having devoted your attention to
my problem.
My Best Regards,
Maury
.



Relevant Pages

  • Re: Convex Functions
    ... let X be a non-empty convex subset of R^n ... Without the hypothesis of continuity, ... Hamel bases and the Cauchy equations ... ... Sorry, quasi, but this isn't true either! ...
    (sci.math)
  • Re: Convex Functions
    ... let X be a non-empty convex subset of R^n ... Without the hypothesis of continuity, ... Hamel bases and the Cauchy equations ... ... Sorry, quasi, but this isn't true either! ...
    (sci.math)
  • Re: Convex Functions
    ... quasi wrote: ... let X be a non-empty convex subset of R^n ... Without the hypothesis of continuity, ... Hamel bases and the Cauchy equations ... ...
    (sci.math)
  • Re: does this function have a local maximum at 3
    ... >>quasi wrote ... >concave up at x=c or concave down at x=c depending on whether f'' ... >concavity is sufficient to insure a relative extreme point -- if f is ... the continuity of f'' does make it visually obvious ...
    (sci.math)
  • Re: continuity of composition of functions
    ... quasi wrote: ... R to R that are nowhere piecewise monotone. ... that the proof only uses continuity of g. ... Which topological spaces X have the following property? ...
    (sci.math)

Loading