Re: HAha!! I HAVE DONE THE GRAPHICS FOR F.L.T. SIMPLE SOLUTION - Adam style...

On Sep 26, 1:12 am, Tonico <Tonic...@xxxxxxxxx> wrote:
On Sep 25, 6:42 pm, finite guy <adamle...@xxxxxxxxxxxx> wrote:





On Sep 25, 11:50 pm, Tonico <Tonic...@xxxxxxxxx> wrote:

On Sep 25, 11:56 am, finite guy <adamle...@xxxxxxxxxxxx> wrote:

On Sep 25, 5:04 pm, Tonico <Tonic...@xxxxxxxxx> wrote:

On Sep 25, 10:49 am, finite guy <adamle...@xxxxxxxxxxxx> wrote:

On Sep 25, 2:45 pm, Tonico <Tonic...@xxxxxxxxx> wrote:

On Sep 25, 2:16 am, finite guy <adamle...@xxxxxxxxxxxx> wrote:

On Sep 25, 5:36 am, Tonico <Tonic...@xxxxxxxxx> wrote:

On Sep 24, 3:12 pm, finite guy <adamle...@xxxxxxxxxxxx> wrote:

Hi
Any of you suckers wanna bet?
We can talk escrow.
Regards
Adam Lewis, Perth.

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Not only it must be hot and boring like hell in Perth: some virus
causing meningitis idioticus must be on the loose there.
Poor perthians...!

Regards
Tonio

No. At the moment it is cold and wet.

I know what you mean, I 'have' to be an idiot. Compared to some, I
am.

When I was sick I halucinated

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There you go: told ya! Poor thing, still sick. Ts,ts,ts!

Regards and feel well soon.
Tonio- Hide quoted text -

- Show quoted text -

I said 'when' I was sick.
You are probably still ill and believe in 'infinite finite'. Infinite
integers...
I am not a rich thing, true. Tsk, tsk, tsk.
Regards also.
Adam.-

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"To believe in infinite finite"?! These are just your hallucinations,
my boy..."inifnite finite" and nonsense like that: ts,ts,ts.
And you also believe....oh well.

Regards and swallow your medicaments
Tonio- Hide quoted text -

- Show quoted text -

Thanks. I did just take a Panadol.

Are integers (being finite) not considered infinite in quantity?

Regards.
Adam.-

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Taking into consideration the way you express yourself, it's crystal
clear not only that you're not a mathematician, but also that you're
not too....uh, how to say it? Well, not too well educated, say.

If you meant to ask whether the set of the integer numbers, aka
Z (from the german word Zahl), Z = {....-3,-2,-1,0,1,2,...} is
infinite, the answer is yes, according to Cantor's definition.
Why? Because the set Z contains a proper subset which has the same
cardinality (again, a notion popped up by Cantor) as Z.

Hopefully that answers your question and sheds some light in that
darkness your knwoledge of basic maths seems to be enveloped.

Regards
Tonio- Hide quoted text -

- Show quoted text -

Thanks. You mean, 'Why yes, Adam, it does seem that finite and
infinite are blurred. I had better rethink a bit.'

You said, finite integers are infinite in quantity... and, therefore,
infinite.
Oh, right. That IS what I said is told.

But it has to do with sets and limits... wrong again.

I rest my case by your words, you dummy (not according to Cantors fiat
statement apparently).
My, what a dark shadow of understanding you do cast regarding the
attributes of finite and infinite.

Tell me, learned one, can YOU make a cube in XYZ? If so, disprove FLT
and Wiles and me.

FLT shows that you cannot go from (1,1,1) to even (2,2,2). You cannot
make any finite unitised cube in XYZ.
As I have said before, the 'origin' point is not (0,0,0)
mathematically. It actually don't work. :-)

Start thinking for yourself from the basics before you run around
disclaiming yourself.

Simple really, do you get it? Fair enough, not without pictures... you
will have to wait only a short time.

Regards.
Adam Lewis, Perth.

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You REALLY should take your medications, Adam...and get some
ventilator in hot Perth, and perhaps dedicate your best efforts to
solve soduku. Sometimes that can be fun...:)

Regards
Tonio

Ps "Cubes" in XYZ...LMAO!!!!!- Hide quoted text -

- Show quoted text -

How do I get me some ventilator? :-)

Anyway, go look at the graphical representation of the FLT problem as
normally presented. Take Simon Singh's illustrations in his book. You
can't combine cubic amounts... cubes of XYZ, to you... without
'losing' a unit.

My representation actually 'shows' the missing unit.

Regards.
Adam.

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