Re: Analysis with sin(1).
- From: Darren <anon5874@xxxxxxxxx>
- Date: Thu, 04 Oct 2007 11:55:06 -0700
On Oct 4, 11:06 am, "mina_world" <mina_wo...@xxxxxxxxxxx> wrote:
"Pubkeybreaker" <pubkeybrea...@xxxxxxx> wrote in message
news:1191520713.318967.91200@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Arturo Magidin wrote:
In article <1191518136.089372.78...@xxxxxxxxxxxxxxxxxxxxxxxxxxx>,
Pubkeybreaker <pubkeybrea...@xxxxxxx> wrote:
Hint:
Is sin(x) < x?????
That guarantees the sequence converges (being monotone decreasing and
nonnegative), but I think it is insufficient to imply that the
sequence converges to 0.
Correct. But we also have lim x-->0 sin(x)/x = 1..
Sorry. I can't follow your thinking.
I need detailed explanation.- Hide quoted text -
- Show quoted text -
Perhaps you could start by proving:
sin(x) < x - x^3/3! + x^5/5!
then if the limit > 0, then you could form a contradiction?
.
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- Analysis with sin(1).
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