Why RP^1 is homeomorphic to S^1 ??
- From: bigli <nimbigli@xxxxxxxxx>
- Date: Fri, 05 Oct 2007 20:57:54 -0700
why RP^1 is homeomorphic to S^1 ?(please with details)
S^1 ={ (x,y) ; x^2 + y^2 =1 } together with induced topology of R^2 or
complex plane
RP^1 ={ { (x,y),(-x,-y) } ; (x,y) is in S^1 } together with quotient
topology induced by f: S^1 -------> RP^1 ; f(x,y)= { (x,y) ,(-x,-y) }
.
- Follow-Ups:
- Re: Why RP^1 is homeomorphic to S^1 ??
- From: Timothy Murphy
- Re: Why RP^1 is homeomorphic to S^1 ??
- From: Kira Yamato
- Re: Why RP^1 is homeomorphic to S^1 ??
- Prev by Date: Re: Report Peeping Tom, also known as 'Google' to the FBI, if you are one of the educated people at least
- Next by Date: Re: Two results of set geometry
- Previous by thread: dim(coker(S))
- Next by thread: Re: Why RP^1 is homeomorphic to S^1 ??
- Index(es):