Not Baffled - Solved
- From: 6E656F <6e656f@xxxxxxxxx>
- Date: Mon, 08 Oct 2007 16:08:57 -0000
Mohan Pawar wrote:
"Mohan Pawar" <Reply@xxxxxxxxxxxxxxxxxxxx> wrote in message
news:470a3ed3$0$19651$4c368faf@xxxxxxxxxxxxxxxxx
and
"6E656F" <6e656f@xxxxxxxxx> wrote in message
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formulae
Rod wrote:
"6E656F" <6e656f@xxxxxxxxx> wrote in message
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(1+0.0775)^(2/12)=1.01252.
I am trying to figure out what the hell this is.
two months interest at 7.75% per year is 1.252%
.
That was very fast. Those people called Actuaries has given
like this...
(1+i)^(n/12) where 'i' is rate of interest i.e 7.75% per annum
'n'years=0.1667.
for number of months.1.1252.
But in example given above, they arrived at 1.01252 and not
How they arrived at 1.01252 ?
Given annual interest rate = 7.75%=0.0775
If loan P = $1.00 and loan period=2 months, then
amount due at the end of 2nd month = 1* (1+0.0775)^(2/12)=1.01252.
In general, worth of P dollars after n periods of time at interest
rate of i% per period is S, where
S=P*[1+(i/100)]^n
You have i=7.75% per year and hence your n must be in years. Your
example assumes loan P=$1 for period of 2 months=2/12
So 0.01252 is practically acceptable amount.Pardon the copy paste typo: "So 1.01252 is practically acceptable
amount."
Pardon the copy paste typo: "(not exactly 1.01252 because now
If the monthly interest was assumed for a $1 loan, then
i(monthly)=0.0775/(12*100)=0.00646 and n=2,
S=1*[1+(7.75/1200)]^2=1.01296 (not exactly 0.01252 because now
interest charged monthly)
interest charged monthly)."
..
Actually this confusion is because of rate of interest. They clearly
mention it 7.75% but while calculating they take it as 7.50%.
0.075*0.16666666666666...= 0.01252.
Also the way formulae is written is wrong.
Thanks.
.
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