Re: Limit

From: "Boen S. Liong" <mr_bean_curdy@xxxxxxxxx>
Date: Sun, 14 Oct 2007 02:45:04 -0700

On 14 Okt, 16:03, Thomas Nordhaus <thnord2...@xxxxxxxx> wrote:

Boen S. Liong schrieb:

Can somebody help with the limit?

How to derive:

limit(u->0) (1-u)^(-1/2) to be (1+0.5u)?

This surely isn't correct. The limit is equal to 1. (1+0.5*u) is the
first order Taylor-approximation however. Just compute it using the
definitions.

Boen S. Liong.

--
Thomas Nordhaus

It is correct. I quote from a math book. My hunch is it is from Taylor
series expansion. Use numerical for u, and you will see. Please check
before you say it is wrong.

Regards,

Boen S. Liong

.

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Relevant Pages

Re: Limit
... Boen S. Liong schrieb: ... first order Taylor-approximation however. ... Thomas Nordhaus ... series expansion. ...
(sci.math)
Re: Limit
... first order Taylor-approximation however. ... Thomas Nordhaus ... The first three terms of the Maclaurin series for ^are ... The binomial series gives the same result. ...
(sci.math)
Re: Limit
... first order Taylor-approximation however. ... I quote from a math book. ... My hunch is it is from Taylor ... series expansion. ...
(sci.math)