Re: Limit

Boen S. Liong schrieb:
On 14 Okt, 16:03, Thomas Nordhaus <thnord2...@xxxxxxxx> wrote:
Boen S. Liong schrieb:

Can somebody help with the limit?
How to derive:
limit(u->0) (1-u)^(-1/2) to be (1+0.5u)?
This surely isn't correct. The limit is equal to 1. (1+0.5*u) is the
first order Taylor-approximation however. Just compute it using the
definitions.



Boen S. Liong.
--
Thomas Nordhaus

It is correct. I quote from a math book. My hunch is it is from Taylor
series expansion. Use numerical for u, and you will see. Please check
before you say it is wrong.

I checked - and: Your book is wrong (provided you cited correctly). limit (u->0) (1-u)^(-1/2) = 1. Your hunch is correct though. Look at the definitions. (1+0.5*u) = f(0) + f'(0)*u is the first order Taylor-approximation near u=0 of the function f(u) = (1-u)^(-1/2).


Regards,

Boen S. Liong



--
Thomas Nordhaus
.

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