Re: product topology
- From: José Carlos Santos <jcsantos@xxxxxxxx>
- Date: Mon, 22 Oct 2007 14:48:26 +0100
On 22-10-2007 14:41, sanchopancho80@xxxxxx wrote:
does anybody know a counterexample for the following statement?
Let X, Y and Z be topological spaces and F:XxY --> Z be a mapping,
such that F(x,-):Y --> Z and F(-,y):X --> Z are continuous for every x
in X and every y in Y. Then F is continuous.
Consider f:R^2 ---> R defined by f(0,0) = 0 and f(x,y) = x.y/(x^2 + y^2)
otherwise. It is discontinuous at (0,0).
Best regards,
Jose Carlos Santos
.
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