Re: Implementable Set Theory and Consistency of ZFC
- From: "Jesse F. Hughes" <jesse@xxxxxxxxxxxxx>
- Date: Thu, 25 Oct 2007 11:07:37 -0400
Han de Bruijn <Han.deBruijn@xxxxxxxxxxxxxx> writes:
Jesse F. Hughes wrote:
Even assuming that there are four models rather than one, so what?
The point is that you have *not* given a proof of (5)-(8) using only
axioms (1)-(4). Thus, you have not done what you said.
Even if you show that there are seven models for (1)-(4) in which
(5)-(8) are also true, you haven't done what you said. Even if you
show there are *infinitely* many models satisfying this condition, you
haven't done what you said. So, perhaps you should either do what
you said or change your claim.
No. Because _nothing_ sensible ever counts as a proof in your conception
of mathematics.
Quite wrong. I've told you what counts as a proof of the claim that
(5)-(8) are theorems of (1)-(4). Namely, a proof of each of (5)-(8)
using only (1)-(4) as axioms.
What is so controversial about that?
Let those who can not keep up do not halt the parade ..
Uh huh.
--
Jesse F. Hughes
"Casting [Demi] Moore as a woman who has come to the New World so that
she can 'worship without fear or persecution' in _The_Scarlet_Letter_
is like casting Bruce Willis as Young Rene Descartes." -Joe Queenan
.
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