Re: Implementable Set Theory and Consistency of ZFC
- From: "Jesse F. Hughes" <jesse@xxxxxxxxxxxxx>
- Date: Mon, 29 Oct 2007 12:26:23 -0400
Han de Bruijn <Han.deBruijn@xxxxxxxxxxxxxx> writes:
Jesse F. Hughes wrote:
Han de Bruijn <Han.deBruijn@xxxxxxxxxxxxxx> writes:
Nothing. I've done just _that_ in my article.Weird. How come no one else can recognize that you've done that?
You forget that 'sci.math' is not "no one else". It's a relatvely small
Internet Cafe, with some really weird inhabitants.
Is there someone else you *have* convinced? Well, no matter. Let me
instead say "no one else of whom I'm aware". And if there *is*
someone who agrees with your claim, by all means let me know.
Also, if you *had* done that, then axioms (1)-(4) + (9) would be
sufficient for ZFC. Don't you find it a touch odd that no one else
has noticed this fascinating fact?
The fact that Infinity X is an axiom of standard ZFC makes it necessary,
it seems, to include the axioms (5-9), in order to make infinite sets
make more "look alike" finite sets. Which wouldn't have been necessary
with a more realistic approach (I mean, e.g. Choice is provable within
the realm of finite sets, as is well known).
You *do* know that if (1)-(4) prove (5)-(8), then so do (1)-(4) + (9),
right?
I can't do any sensible reasoning with Infinity (9 = X right?)
included.
It is an well-formed formula, yes? And thus, we can consider a theory
in which (9) (or X, whatever) is an axiom. So if you can't do any
sensible reasoning with (9), it appears to be a personal issue.
--
"[Sometimes, I don't know what to do] so I guess. Technically what I
do is called making a hypothesis. It's like what physicists do, and I
basically operate a lot like a theoretical physicist."
-- James S. Harris
.
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