Re: calculous in the curve space theorem 1



On Oct 31, 12:25 am, caoyanwh2003 <caoyanwh2...@xxxxxxxxxxx> wrote:
Calculous in the curve space:

Throrem 1: Y=?dxdx=1

Today's lesson is: USENET IS A PLAIN TEXT MEDIUM. That means no
pictures, no sound files, and no "special characters". Some
newsreaders will convert any "special characters" into question marks,
which makes the post unreadable.

Try again, this time only using the symbols !@#$%&'()*+,-./
0123456789:;<=>?
@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}

--- Christopher Heckman

P.S. And get the spelling right.

The meaning of maths is as following (figure 1),
image address:bbs.php?
xname=A8QJCV0&action=xfile&bpos=24&bid=101&fname=729221_figure1.JPG

there is a line L above the X-axis, the line L is parallel with the X-
axis, dx is the distance from the line L to the X-axis, when dx?0, it
means in the maths the line L is constantly close to the X-axis,
namely dx=1/?,and the length of the line L is : L???

the meaning of the formula Y=?dxdx

in the maths is :the area of the line L to the X-axis.

Namely L?dx=(1/?)??=1

So we can conclude: Y=?dxdx=1

The theorem 1 is the first theorem in the calculous in the maths. The
theorem 1 shows: although the line has no area, we cann't say the
area of the line is zero. Because in every area which is unit 1 , it
is made up of much much more lines, and every area of the line is: L?1/
??0,but it is not zero, it is two things.

The theorem 1 also shows, y is not the area of the line of X-axis, it
is just the area when the L?X-axis, the area from L to X-axis.

The theorem 1 tell us in the formula of calculus, even if a very very
less dx, we cann't think the dx is zero in the calculus, because the
dx is been integral, it is also a very big number: 1.
Cao's theory

2007-4-20

http://thre-firewh2.home.sunbo.net/


.



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