Re: calculous in the curve space theorem 1
- From: Proginoskes <CCHeckman@xxxxxxxxx>
- Date: Wed, 31 Oct 2007 08:17:31 -0000
On Oct 31, 12:25 am, caoyanwh2003 <caoyanwh2...@xxxxxxxxxxx> wrote:
Calculous in the curve space:
Throrem 1: Y=?dxdx=1
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--- Christopher Heckman
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The meaning of maths is as following (figure 1),
image address:bbs.php?
xname=A8QJCV0&action=xfile&bpos=24&bid=101&fname=729221_figure1.JPG
there is a line L above the X-axis, the line L is parallel with the X-
axis, dx is the distance from the line L to the X-axis, when dx?0, it
means in the maths the line L is constantly close to the X-axis,
namely dx=1/?,and the length of the line L is : L???
the meaning of the formula Y=?dxdx
in the maths is :the area of the line L to the X-axis.
Namely L?dx=(1/?)??=1
So we can conclude: Y=?dxdx=1
The theorem 1 is the first theorem in the calculous in the maths. The
theorem 1 shows: although the line has no area, we cann't say the
area of the line is zero. Because in every area which is unit 1 , it
is made up of much much more lines, and every area of the line is: L?1/
??0,but it is not zero, it is two things.
The theorem 1 also shows, y is not the area of the line of X-axis, it
is just the area when the L?X-axis, the area from L to X-axis.
The theorem 1 tell us in the formula of calculus, even if a very very
less dx, we cann't think the dx is zero in the calculus, because the
dx is been integral, it is also a very big number: 1.
Cao's theory
2007-4-20
http://thre-firewh2.home.sunbo.net/
.
- References:
- calculous in the curve space theorem 1
- From: caoyanwh2003
- calculous in the curve space theorem 1
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