Re: Volume integrals

Maybe its easier in polar coordinates.


"saneman" <yyyy@xxxxxx> wrote in message
news:fg8ilq$o41$2@xxxxxxxxxxxxxxxxxxxx
The function f(x,y,z) = y is defined on the domain:

{(x,y,z) | 0 <= y, x^2+ y^2 + z^2 <= 1}

When finding the integral I need to have upper and lower bounds. So far I
have found:

y2 <= 1-x2-z2 <=>
y <= sqrt(1-x2-z2)

I then have:

0 <= y <= sqrt(1-x2-z2)

and can then repeat for z and x:

z <= sqrt(1-x2-y2)
x <= sqrt(1-z2-y2)

But then I still need the lower bounds for z and x or am I approaching the
problem in a wrong way?


.

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