Re: Implementable Set Theory and Consistency of ZFC



On Oct 31, 7:57 am, Han de Bruijn <Han.deBru...@xxxxxxxxxxxxxx> wrote:
Jesse Hughes wrote:

Whatever. Again, I ask: Do you agree that "There is at most one empty
set" is a theorem of ZFC, *even though* it uses only one of the axioms
of ZFC?

Yes.

The proof of existence uses an instance of separation and uniqueness
uses extensionality. Or, if you have an empty set axiom, then, yes,
just one axiom.

But aside from those pedantic matters, now you see our point, right?
The proof of a theorem might use only certain premises but it is still
a theorem from any larger set of premises, just as this is an example:
the proof of the existence of a unique empty set needs to use only
certain axioms, not all of them, but the existence of a unique empty
set is also a theorem of the entire set of axioms.

MoeBlee


.



Relevant Pages

  • Re: Cantors circular "proof" that evens = integers
    ... is that, assuming consistency of the axioms of ZFC, that infinite ... infinite sets logically possible entitites if ZFC is consistent but proves ... If ZFC is consistent but proves "ZFC is inconsistent" then ... Also it seems, BTW, that such a proof would have to be a pure existence ...
    (sci.logic)
  • Re: set builder
    ... >existence of an empty set phi. ... Using various axioms, ... >The only sets that can be shown to exist in ZFC are those that can be ... >contradictions of naive set theory. ...
    (sci.math)
  • Re: tommy1729 set axioms update
    ... For a long, long time, '0' has been used for the empty set. ... We're talking about the axioms you set up and the ... define such notation from your primitives or take it ... ZFC has INFINITELY many axioms. ...
    (sci.math)
  • Re: Cantor Confusion
    ... existence of a number is independent of the existence of a representation. ... But this is *not* a circular definition. ... operations) using the Peano axioms. ... Axioms state what things exist in their realm. ...
    (sci.math)
  • Re: set builder
    ... Using various axioms, ... The only sets that can be shown to exist in ZFC are those that can be ... I don't start by postulating the existence of any ... contradictions of naive set theory. ...
    (sci.math)

Loading