Re: Maybe Exponential? check it out
- From: quasi <quasi@xxxxxxxx>
- Date: Sun, 04 Nov 2007 17:45:31 -0500
On Sun, 04 Nov 2007 16:29:21 EST, Craig <rocketsummerband@xxxxxxxxx>
wrote:
Hi,
just looking for the probability that AT LEAST half of them need to wait more than 6 minutes to get their pizza
one customer per pizza, full pizza, one week (doesn't matter if theyre open 24/7)
Of course it matters. The more time in a week, the more spaced out the
calls will be, on average. For example, suppose the shop was only 1
hour every day. Or, more blatantly, suppose the shop was only open for
15 minutes every day! Then there would be lots of waiting, and lots of
unfilled orders (unless they stayed until the pizza was done, just
closing the phones after 15 minutes).
The customers just call to get a pizza, 250 of them, in one week.
Just because the time to make a pizza is exponentially distributed doesn't neccessarily mean we need to use that to solve the question
But it's definitely relevant. If the distribution for the time to make
a pizza is unknown, then knowing the average time is 6 minutes is not
sufficient to answer the question.
Also, you need to make some assumption about the distribution of
customer calls. Do they all call within the first 6 minutes of the
week? No? Then how are the calls distributed? Exponentially?
Uniformly? If the calls are distributed exponentially, then is 250 the
mean number of calls rather than the exact number of calls?
quasi
.
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