Re: Confirmation of Shannon's Mistake about Perfect Secrecy of One-time-pad

On Nov 6, 8:38 am, wangyong <hell...@xxxxxxx> wrote:
=============your proof is just I gave.
The probability is under the case c is not fixed,

I *start* with the unconditional probabilities

as when c fixed, the probability distribution changed,

Of course. And I computed those changes.

you admit that probability of K is changged,
how can you insure other
probability is not changged,

A probability may or may not change.
To find out which I computed the
conditional probabilities using
the definition of conditional probability
When I computed the conditional probabilites
I found that the probability distribution
of K changed but the probability distribution
of M did not.

how can you use the condition c is not
fixed, K and M is independant , to compute the probability when c is
fixed, that case k and m are dependant.

It is easy to see from the
definition of a conditional probability distribution
that if you have the full unconditional probability distribution
you can determine the conditional probability distribution.
I first used the condition c is not fixed, K and M
are independent to compute the unconditional probability distribution,
then used the definition of a conditional probability distribution
to get the probabilities when c is fixed.

- William Hughes

.

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