Re: Directional derivative in l^1 space
- From: The World Wide Wade <aderamey.addw@xxxxxxxxxxx>
- Date: Tue, 13 Nov 2007 11:24:20 -0800
In article
<2622413.1194958530126.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxx>,
precarion <precarion@xxxxxxxx> wrote:
Hello!
Can anyone help me with this problem:
"Let:
X = l^1 := { (x_n) - sequences of real numbers, such that sum of |x_n| for n
= 1 to +oo is less then infinity};
f = ||(x_n)|| := sum of |x_n| for n = 1 to +oo;
(x_n)* - some choosen sequence from X.
Check if the following to statements are equivalent:
(1) for every sequence h in X there exists a directional derivative f'_h
(x_n)* (it means: the directional derivative of f on (x_n)* in the direction
given by vector h),
(2) every term of (x_n)* is nonequal to 0 (i.e.: for every n in N: (x_n)* !=
0 )."
------
Chris
Hint: Try it in R^2 first, where for example you see D_h(f)(1,-1) =
h_1 - h_2. In l^1 the guess would be D_h(f)(x) = sum(n=1,oo) a_n*h_n,
where a_n = 1 if x_n > 0, a_n = -1 if x_n < 0.
.
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