Re: #299 All Possible Digit Arrangements gives order and pattern to the Reals and makes them Countable; new textbook: Mathematical Physics (Reals & Counting Numbers/AP-adics Primer) for age 6 years onward



a_plutonium <a_plutonium@xxxxxxxxxxx> writes:

The number is
1x10^0 + 2x10^1 + 3x10^2 + 4x10^3 + 5x10^4
+ 0x10^5 + 0x10^6 + 0x10^7 + ... + 5x10^{oo - 4}
+ 4x10^{oo - 3} + 3x10^{oo - 2} + 2x10^{oo - 1}
+ 1x10^oo

Duh.

Pretty good, but we can replace the infinity symbol with the world's
largest integer 999....99999

We can?

Okay, but then if we apply the same reasoning to *that* number, we
find that 999....99999 is defined as

9x10^0 + 9x10^1 + 9x10^2 + ... + 9x10^{999....9999 - 2}
+ 9x10^{999....9999 - 1} + 9x10^999....9999

So, 999....9999 > 9 x 10^999....9999. Does that seem right to you?


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Jesse F. Hughes
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