Re: 1^2 =3, Discovered



Hi Dr. Hossan Aboulfotouh:
Geometry is the invincible foundation of the natural numbers.

The geometry or structure of every natural number is the isosceles triple.
Such that, the square of every possible natural number, equals the total sum of its isosceles triplet.

Hence, number one is a triplet of 1, 1, 1 and the square of one equals 1 + 1 + 1 = 3.

Number two is a triplet of 2, 1, 1 and the square of two equals 2 + 1 + 1 = 4 . . .

Now, here is your question for me:
"If, as you have said, the square root of 3 equals 1 !!!!!
Then, tell me what is the square root of 2, based on your discovery."
Dr.Aboulfotouh,
From the geometric structures of the natural numbers one and two, as I indicated above, the square root of 3 is 1, and the square root of 4 is 2.

The least possible polygon is the unit triangle(unit equilateral triple).In this discovery, there exists no geometric basis for the square root of 2, as there is no geometric necessity for the square root of one, because there are no isosceles triplets smaller than the unit
isosceles triplet 1, 1, 1 or 3.

In the real geometry of the material Universe, one-sided and two-sided triplets or triangles are impossibles.
So, you can see clearly why and how, the geometry of square root of 2 and 1,would be meaningless in the context of the discovery of 1^ = 3.

Thanks for your interest,
-Aiya-Oba.
.



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