Re: Confirmation of Shannon's Mistake about Perfect Secrecy of One-time-pad

On 11月11日, 下午7时37分, matt271829-n...@xxxxxxxxxxx wrote:
On Nov 11, 3:18 am, wangyong <hell...@xxxxxxx> wrote:





On 11 10 , 8 53 , matt271829-n...@xxxxxxxxxxx wrote:

On Nov 10, 3:23 am, wangyong <hell...@xxxxxxx> wrote:

On 11 9 , 8 02 , matt271829-n...@xxxxxxxxxxx wrote:

Just for a moment, forget the OTP problem. Pretend that you've never
even heard of the OTP. Please study the following question.

I have two coins, one red and one blue. Both are marked "0" on one
side and "1" on the other, and both are fair (i.e. they both come up
"0" with probability 1/2, and "1" with probability 1/2). I toss both
coins. The red coin comes up with the number R. The blue coin comes up
with the number B. I calculate C = R Xor B, and I find that C = 0.
Given that C = 0, what is the probability that R = 0?

Do you think that this question has a well-defined single numerical
answer?

(Please try to give a direct reply to the actual question that I have
asked. If possible, please begin your reply with the word "yes" or the
word "no".)- -

- -

yes

Great. I think that's the first of your replies that I've completely
understood!

Now let me change the problem slightly. Instead of the red coin being
fair, it will be biased. I'll state the new problem in full:

I have two coins, one red and one blue. Both are marked "0" on one
side and "1" on the other. The red coin is biased and comes up "0"
with probability p and "1" with probability 1-p. The blue coin is
fair: it comes up "0" with probability 1/2, and "1" with probability
1/2. I toss both coins. The red coin comes up with the number R. The
blue coin comes up with the number B. I calculate C = R Xor B, and I
find that C = 0. Given that C = 0, what is the probability that R =
0?

Do you think that this new problem has a well-defined single answer
(in terms of p)?

If so, what do you think the answer is?- -

- -

you just no see the contrastion. take the question easy.
If c fixed, k and P are dependant,
but you just use the probablity c not fixed, that is a mixture, and
changged the probablity characteristic,including the value.
can you prove probabilities when c not fixed, the same as
probabilities when c not fixed.

I have no idea what you are talking about.

I asked you two simple questions:

1. Do you think that this new problem has a well-defined single answer
(in terms of p)?

2. If so, what do you think the answer is?

Please just answer the questions. Please answer "yes" or "no" to
question 1. If you answered "yes" to question 1 then please also
answer question 2.- 隐藏被引用文字 -

- 显示引用的文字 -
--------this new problem
what problem??? you just not tell? how can i answer.
.

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