Re: #320 I concede that 10^9999....999999 is (pi) and where 10^999...9998 is ; new textbook: Mathematical Physics (Reals & Counting Numbers/AP-adics Primer) for age 6 years onward

a_plutonium <a_plutonium@xxxxxxxxxxx> writes:

Okay, I am going to concede to Jesse over this issue. That I was
wrong.

And the number 9876.....54321 is decimal notation represented by this:

9 x 10^9999....99998 + 8 x 10^9999....999997 + ....

I had previously written it this way but I wanted to use every
Counting Number
even the largest 9999.....999999

What has persuaded me is that the Reals make sense only when the
largest decimal
is 10^(-)9999....99998

Same issue.

If I start counting at 0, I get to 1 at the same time as I get to 10^0.
I get to 2 before I get to 10^1.
I get to 3 before I get to 10^2.
I get to 4 before I get to 10^3.

and so on, but I get to 10^{999....998} before I get to 999....999.

Thus, there is some n such that

If I start counting at 0, I get to n before I get to 10^{n-1}, but
I get to 10^{n} before I get to n+1
(or maybe at the same time).

As lwalke3 pointed out, this would mean:

I get to n before 10^{n-1},
to 10^{n-1} before 10^n,
to 10^n before or at the same time as n + 1

and thus, there is at least one number between n and n + 1.


--
What you want with a hen What you want with a woman
Won't cackle when she lays? when she won't do nothin' I say?
What you want with a hen -- Charlie Patton,
Won't cackle when she lays? "Banty Rooster Blues"

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