Re: The infintely small number b
- From: Venkat Reddy <vreddyp@xxxxxxxxx>
- Date: Sun, 18 Nov 2007 09:28:41 -0800 (PST)
On Nov 18, 1:31 pm, lwal...@xxxxxxxxx wrote:
On Nov 17, 6:33 pm, Venkat Reddy <vred...@xxxxxxxxx> wrote:
On Nov 18, 3:44 am, lwal...@xxxxxxxxx wrote:
I'm not quite sure why VR defines b / b as 1, butThanks for noticing. Thats an error and I've posted a correction
leaves b - b undefined
immediately. b/b is undefined too.
Now with VR's correction, there's another way to interpret
what VR is writing, using either hyperreals or surreals this time.
Here 0 is zero of course, b is a strictly positive infinitesimal,
n is a positive number that is neither infinite nor infinitesimal
(some nonstandard analysts call such values "appreciable"),
and Inf is a positive infinite value.
We now look at VR's rules again:
Operations with zero (non-existence of extent)
b + 0 = b
An infinitesimal plus zero is still infinitesimal.
b - 0 = b
An infinitesimal minus zero is still infinitesimal.
b * 0 = 0
An infinitesimal times zero is zero.
(b / 0) is undefined and not to be taken as inf.
Division by zero is undefined even for infinitesimals.
Operations with itself
b + b = b
The sum of two positive infinitesimals is still a
positive infinitesimal.
b * b = b
The product of two infinitesimals is still infinitesimal.
b/b is undefined too.
The quotient of two infinitesimals may be infinitesimal,
appreciable, or infinite. Indeed, if in the surreals, we
let x = epsilon and y = epsilon^2, then y/x is
infinitesimal, x/x is appreciable, and x/y is infinite.
(b - b) is undefined.
The difference of two positive infinitesimals may be
positive, zero, or negative. Indeed, x-y is positive,
x-x is zero, and y-x is negative.
Operations with n where b<n<inf:
n * b = b
The product of an appreciable number and an
infinitesimal is still infinitesimal.
n / b = inf.
The quotient of an appreciable number and an
infinitesimal is infinite.
(n/0 is undefined and can not be taken as inf.)
Division by zero is undefined, even in the
hyperreals and surreals.
n + b = n + b
n - b = n - b
The sum or difference of an appreciable number
and an infinitesimal is still appreciable.
But of course, we now wonder why VR wants to
distinguish among n+b, n, and n-b.
At this point, we must remind ourselves what
VR's original intent in coming up with the new
infinitesimal b in the first place. Although VR has
not stated his purpose in this thread, in other
threads, he points out that he wants to assign
measures to sets such that proper subsets of
bounded intervals have strictly smaller measures.
VR hasn't told us, but I can make the educated
guess that he wishes to assign measures to
intervals as follows:
Closed interval [x,y] has measure y-x+b.
Semiopen interval [x,y) has measure y-x.
Open interval (x,y) has measure y-x-b.
The degenerate interval [x,x], which is actually the
singleton {x}, would have measure b. The empty
set would have measure 0. And of course, an
unbounded interval would have measure inf.
Although VR achieves his purpose of assigning
strictly smaller measures to proper subintervals of
bounded intervals, it doesn't necessarily assign
strictly smaller measures to proper subsets that
are not intervals. Indeed, notice that:
[x,y] has measure y-x+b
(x,y) has measure y-x-b
[x,y] \ (x,y) = {x,y}
{x,y} has measure (y-x+b) - (y-x-b) = b+b.
By VR's rules above, b+b = b. So the set with
two elements, {x,y}, would have the same measure,
namely b, as its singleton subsets. The problem,
of course, is that VR has not demonstrated how to
find measures of sets that are not intervals.
We know that non-Lebesgue measurable sets
exist (in ZFC, including the Axiom of Choice). I
wonder whether non-VR measurable sets exist.
I'm afraid your interpretation implies that the points, denoted by
real numbers, have an extent of b. No, I did not mean b to represent a
measure of a point. It is a measure of the smallest non-zero extent,
which is not just a "location". From what I learnt now, b appears
closer to hyperreal infinitesimal than surreal one. Still it is
different from both because, for example, none of them mentioned self
inequality and additive operations with n resulted in treating the
infinitesimal as zero.
I thought b + n is better left that way because b is something like
the imaginary number i or the dx in calculus. It can't participate in
a addition or subtraction in a meaningful way. b is just a
characteristic of the extent and the DNA for the growth of the number
and extent. However you can't ignore it as zero.
As I mentioned in my other post, I do understand that the set of reals
is a dense set and one can find a new point (number) between any two
given points. But this process can only tell us that we may be able to
"fill in" an existing extent with points but does not tell us how the
extent came into existence.
So I think it more sensible to have an infinitely small number that
represents existence of an extent in its smallest measure, than
collapsing it with zero, the non-existence. Surely, b is not a real
number and it is as imaginary as infinite.
Regarding sets, interval and measure: Defining an interval as a set of
all real numbers between a given pair of real numbers is dependent on
assumption that the interval is made up by distinct real numbers. Such
an interval doesn't have distinct and different elements, unless those
element values are explicitly specified. It is just continuum. You
can't break it into pieces of points or real numbers. [x,x] has zero
measure.
- venkat
.
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