Re: Dodecahedron Inside a Sphere?

I found that I could use almost the same method as described in my original
post for putting an icosahedron inside a sphere, and I get the value:

Theta(L) = 63.43494882 degrees

So I should be able to cut 30 pie-wedges with this angle and make a sphere
of 20 triangular pyramidal voids.

Also, let L/R be the ratio of a polyhedron edge to the radius of the
enclosing sphere.

For a dodecahedron in a sphere I get:
L/R = 0.71364418

For an icosahedron in a sphere I get:
L/R = 1.051462224


.

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