Re: Topological Metric Space vs. Metric on a Manifold
- From: Gonçalo Rodrigues <nospam@xxxxxxxxxxxx>
- Date: Sun, 09 Dec 2007 01:10:00 +0000
On Sat, 8 Dec 2007 19:32:05 -0500, "David Park" <djmpark@xxxxxxxxxxx>
fed this fish to the penguins:
If I use a distance function to make R^n into a 'Metric Space' and then use
this to make charts for a manifold,
What do you mean by this?
does that imply that there is any kind
of metric on the manifold? I say the answer is no, it only gives us a
concept of nearness and continuity on the manifold and it would take extra
structure to put a metric on the manifold.
Correct, a manifold structure does not imply the existence of a
metric. Or more correctly, one can prove that it is possible to come
up with a metric on a manifold that is compatible with the topology
(with the usual definition of manifold that entails countability
assumptions) but this metric is highly non-unique, non-canonical, and
always involves some arbitrary choices.
By the way, this is a purely topological result, the differentiable
structure is irrelevant for the matter.
So when someone says that such a space is a metric space, it (almost)
always implies a *choice* of an *extra* structure in terms of a
definite metric that has a special relevance for this or that problem.
Best regards,
G. Rodrigues
Note: one must be careful with the terminology here. A Riemannian
structure is also called a metric in many quarters. But the same
answer stands: while it is possible in every manifold to put a
Riemannian structure, it is non-unique, non-canonical and always
involves some arbitrary choices.
.
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