Re: reply to "Re:...conventions...,0^0=?"

On Dec 9, 8:36 pm, lowlymather <sum_sk8r_d...@xxxxxxxxxxx> wrote:
i thought you used l'hopital's rules here
0^0
take natural log ln(0^0)= 0ln0 = 0 * infinity
0 * infinity = 0 * 1/0

Only when taking limits.

Everywhere I've seen 0^0 used, it's been defined to be 1, such as in
the formula for the Taylor series of a function:

sum(f^(n)(a)/n! (x-a)^n, n=0..infinity)

The n=0 term, when x=a, is f^(0)(a)/0! (a-a)^0 = f(a)*0^0, and this
needs to be f(a), so 0^0 is defined as 1 with dealing with polynomials
and series.

--- Christopher Heckman
.

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