Re: Need Help - Thank you from Noury Goujjane

On Dec 18, 3:16 pm, Noury Goujjane <noury-goujj...@xxxxxxxxxxxxxxxx>
wrote:
My firend has challenged me with this one:

y^x = x^y + 1
you must solve for y as a function of x

Any Thoughts
Noury Goujjane

How about 3^2 = 2^3 + 1?

Of course, this is just one solution.

GrafEq suggests multiple curves...

Drop me an e-mail and I'll send you the jpg I took of this.
(Better email: DrMWEcker at aol dot com)

Dr. Michael W. Ecker
Associate Professor of Mathematics
Pennsylvania State University
Wilkes-Barre Campus
Lehman, PA 18627

Better email: DrMWEcker at aol dot com
.