Re: Computability

So.

From x^p + y^p = z^p we have many statements in MA. Much of what
follows was shown to me here in sci.math.

x^p + y^p == 0 mod z
x^p / y^p == 1 mod z
(x/y)^p == 1 mod z
and so y is an invertible member of Z.z*. Likewise (E means Exists)
E /x in Z.z*, /x in Z.y*, /(z mod y) in Z.y*,
E /(z mod x) in Z.x*, /(y mod x) in Z.x*.

Hm. Look at all the invertible elements. Looks like we have ring
theory now, not just group theory.

In words, x,y, and z must each be invertible in each other's rings,
and share no common factor pairwise.

Doug
.

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