Re: Computability
- From: The Dougster 22044 <DGoncz@xxxxxxxxxxxx>
- Date: Sun, 13 Jan 2008 16:34:45 -0800 (PST)
On Jan 10, 11:16 am, quasi <qu...@xxxxxxxx> wrote:
You claimed to have checked it up to z = 256, but apparently you
missed the following counterexample:
(x,y,z) = (74,129,143) which has signature (6,3,3).
Wow. At first I thought this was a candidate triple, because for this
triple (x,y,z) the following are indeed all true:
x < y < z < x+y
(x,y) = (y,z) = (z,x) = 1
o(x/y,z)/2 = o(z/x,y) = o(z/y,x) = p in Po, the odd primes ( o = 3
here)
but then I went back and checked more rigorously and checked
probablilities, too.
at probability = about 29%, x < y < z < x+y
at probability = about 21%, (x,y) = (y,z) = (z,x) = 1 independently
at probability = << 1%, o = odd prime independently of the above
at probability so far zero, (x/y)^p == -1 but only in combination with
the above 3.
and that last is the test for which this fails. As one might expect,
with such a tiny probability that might slip through, so yes, while
it has the signature, it doesn't pass that one test:
(x/y)^p == 143 - 105 == -38, not -1 which would be 142 mod 143
This comes from the first derivation I made in modular arithmetic, way
back, gosh, it was mentioned near the beginning of this thread, and in
2004, I think:
From
x^p + y^p = z^p we have
x^p + y^p == 0 mod z, and so
x^p == -(y^p) mod z, and
(x^p)/(y^p) == -1 mod z, and
(x/y)^p == -1 mod z, where
/y means the multiplicative inverse of y in the reduced residues of z,
that is, in what my text calls Zz*.
Darn. For a moment, there, I thought I'd finally be able to drop this
search! Only around 8 times as many triples to check to limit = 256,
but sooo many to limit = 65535. Dang it, Chip Eastham, you rascal,
what were we/I thinking!?
Thanks to quasi for the smallest triple with the right prime
signature. Well done!
(74, 129, 143) Really, that is good work. To limit = 143, my program
checked 1,415 triples coprime and with the inequality, from 343,000
generated triples. Wow.
Doug
P.S. The smallest triple with the inequality and the coprimality is
the classic (3,4,5)...
P.P.S. I think another condition is x + y == z mod p. I am working to
understand that one....
.
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