Re: Generalized Newton's binomial theorem

On Wed, 16 Jan 2008 03:02:56 -0800 (PST), zeremonial@xxxxxxxxxx wrote:

if x*y=y*x then (x+y)^n = sum_k ( (n! / (k!(n-k)!)) * (x^(n-k))
* (y^k) )
if x*y<>y*x then (x+y)^n = ?

Try it yourself for small n, for example n = 2 and n = 3.

You'll see that there are no like terms.

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