Re: Help Needed
- From: carkaci <carkaci@xxxxxxxxx>
- Date: Wed, 16 Jan 2008 04:06:36 -0800 (PST)
On Jan 16, 1:53 pm, William Elliot <ma...@xxxxxxxxxxxxxxxxxx> wrote:
On Wed, 16 Jan 2008, carkaci wrote:By the way n is not a power of function.
I have a following recurrence relation
y_0 = f ( x )
y_1 = f ( y_0 )
y_2 = f ( y_1 )
..
..
y_n= f ( y_(n-1) )
where n is +inf.
I know that y_n = sin(x), how can I find f(x) ?
Restatement?
If lim(n->oo) f^n(x) = sin x, what is f(x)?
There is not such f.
sin f(x) = lim(n->oo) f^n(f(x)) = lim(n->oo) f^(n+1)(x)
= lim(n->oo) f^n(x) = sin x
some k in Z with f(x) = 2.pi.k + x
lim(n->oo) f^n(x) = oo if, 0 < k
= x, if k = 0
= -oo, if k < 0
----
Restatament : f( f( f( f( f( f( f( f( .....f(x).....) ))))))) = sin(x)
I am looking for function f?
.
- Follow-Ups:
- Re: Help Needed
- From: quasi
- Re: Help Needed
- References:
- Help Needed
- From: carkaci
- Re: Help Needed
- From: William Elliot
- Help Needed
- Prev by Date: Re: the need for relevance
- Next by Date: Re: the need for relevance
- Previous by thread: Re: Help Needed
- Next by thread: Re: Help Needed
- Index(es):