Re: dense in the rational numbers?

On Thu, 17 Jan 2008 rogersteph@xxxxxxxxxxxxxx wrote:

Say one has arbirary n, k where n and k a natural numbers.

If one looks at the set created by the euqation:

(3k + n + 1)^{k-1} (3k + n + 1)! / (4k + n)!

What equation?

Does the set form a dense subset of the rational numbers? (considering
the usual order <)

I'd help were you to explicitely state the set that your
supposed equation creates.

I assume probably not, but how does one find an interval? Or is it in
fact dense?

Intervals are easy to find.
Just pick up on any two different reals.
Call them 'b' for big and 's' for small.

Between them is the interval (s,b) = { x | s < x < b }

I really can't figure out this problem...

Neither can I.

A is a dense subset of the rationals Q when
cl_Q A = Q,

the closure of A within the space of rationals Q, is Q.

A dense subset A of the reals, which is a subset of Q
Is a set with A subset Q, cl A = B. You need to clarify
which you were thinking.




.

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