Area of an ellipse
- From: ms <silvertonm@xxxxxxxxx>
- Date: Sat, 26 Jan 2008 20:01:35 -0800 (PST)
Is there an equation for a certain shaded area of an ellipse, in which
the shaded area is not necessarily a part of the major or minor axes?
I am trying to calculate the angle at which the area of a quadrant of
the ellipse is equal for both halves of the quadrant. I know that the
area is pi*a*b (in which my a = 7.5 and b = 6.25; entire long axis is
15 and shorter axis is 12.5 in length). So, the area for the entire
ellipse would be pi*7.5*6.25 = 147.26. So the area of a quadrant
would be 147.26/4 = 36.82. So I would like to know what the angle
would be to cut this quadrant of the ellipse at a diagonal (through
the center or intersection of a and b) so that the area of the two
portions are equal (18.41 for each portion of the quadrant).
This is not a homework problem, and would be more confusing to
describe what this is for, but any help would be greatful.
.
- Follow-Ups:
- Re: Area of an ellipse
- From: no comment
- Re: Area of an ellipse
- From: David W . Cantrell
- Re: Area of an ellipse
- Prev by Date: proving limit for given values of epsilon
- Next by Date: Re: JSH: A solution to the factoring problem
- Previous by thread: proving limit for given values of epsilon
- Next by thread: Re: Area of an ellipse
- Index(es):
Relevant Pages
|
