Factor x^12+15/11*exp(1/3*x^3) as a product of 6 reals.

Hi all,

how easy or difficult is this REAL factoring challenge?
I could be totally wrong but it doesn't look easy to me at all.

After tinkering a bit with this i came to the conclusion that

x^12+15/11*exp(1/3*x^3)

can be written as a product of maximum 6 reals.

For example for x=2 we get:

2^12+15/11*exp(1/3*2^3)=4115.6253401297498556...

which can be written as a product of R1*R2*R3*R4*R5*R6 reals.

The smallest factor being R1=0.69084445965123865356...

And i am sure that someone can show me
how easy it is to determine the other factors.

regards

Gerry
.