sum question
- From: quebecstat <quebecstat@xxxxxxx>
- Date: Tue, 5 Feb 2008 07:15:27 -0800 (PST)
What is the value of
sum_{k=1}^n (n-k) *a^k =sum(k=1 to n, (n-k)*a^k)
when 0<a<1
.
- Follow-Ups:
- Re: sum question
- From: The World Wide Wade
- Re: sum question
- From: Torsten Hennig
- Re: sum question
- From: Fatal
- Re: sum question
- Prev by Date: Re: Bisection method: your recommendation
- Next by Date: Re: Probability Problem - Sets
- Previous by thread: Bisection method: your recommendation
- Next by thread: Re: sum question
- Index(es):
