Re: sum question
- From: Fatal <fatal@xxxxxxxx>
- Date: Tue, 05 Feb 2008 16:21:31 +0100
quebecstat a écrit :
What is the value of
sum_{k=1}^n (n-k) *a^k =sum(k=1 to n, (n-k)*a^k)
when 0<a<1
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