Re: 1-1/2+1/3-1/4+1/5-1/6+1/7
- From: "Jesse F. Hughes" <jesse@xxxxxxxxxxxxx>
- Date: Tue, 12 Feb 2008 07:01:59 -0500
G. Frege <nomail@invalid> writes:
For simplicity we assume that n, m are in N, then we can write:
x e E* <-> AnEm >= n: x e E_m,
x e E <-> EnAm >= n: x e E_m.
*
Thinking about it, I get the following criteria for the limit - if it
exists:
E = lim E_n
n
iff
x e E <-> EnAm >= n: x e E_m for all x.
With other words, x is element of the limit (if it exists) iff it is not
element _only_ of finitely many elements E_n.
Just to be clear: lim E_n = E ?
n *
Or am I missing something? If I read you right, I guess I don't see
much need to discuss the lim sup and lim inf at present, since we
haven't discussed lim sup and lim inf is just another name for lim.
Surely I'm missing something.
--
Jesse F. Hughes
"I don't know if you noticed but I had a tremendous drop in confidence
concomittant [sic] with a dramatic grip of existential crisis."
--- James S. Harris even has better diseases than you
.
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