Re: continuity of piece-wise defined function

On Feb 17, 11:12 pm, Tim Little <t...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
On 2008-02-18, conrad <con...@xxxxxxxxxx> wrote:

I have the following function:
f(x) = { 1 + x^2 if x <= 0, 2 - x if 0 < x <= 2, (x - 2)^2 if x > 2 }
[...]
But why is it not continuous from the left at 2?

What makes you think it is not continuous at 2?


Because my book only lists to the left
at 0 as a solution.

--
conrad
.