Re: lebesgue
- From: The World Wide Wade <aderamey.addw@xxxxxxxxxxx>
- Date: Thu, 21 Feb 2008 11:27:52 -0800
In article
<432dbdab-0a93-4a80-9764-b4723510515b@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
v_aylin2000@xxxxxxxxxxx wrote:
On 21 È?ubat, 13:06, Robert Israel
<isr...@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote:
v_aylin2...@xxxxxxxxxxx writes:
f is a nonnegative and integrable over a measurable set E. Then
epsilon greater than 0 and delta greater than 0 s.t. over a measurable
set A subset of E with
lamda(A)<delta, we have integral_A f d lambda < epsilon
it means A has measure zero.If A has measure zero we can say lambdaA=0
then,
lambdaA=0 and f is measurable integral_R f X_A dlambda=0
we know that if A subset of E
integral_A f dlambda= integral_R X_A f dlambda<=integral_R X_E
dlambda=
integral_E f dlambda
from this
0<= integral_R X_E dlambda=integral_E f dlambda
What should I do now?
That depends on what you're trying to do, which is not at all clear.
What exactly is the problem you're trying to solve? Â Please be careful
to include the quantifiers (for all) and (there exists), and in the correct
order: they are very important.
--
Robert Israel        isr...@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics     http://www.math.ubc.ca/~israel
University of British Columbia       Vancouver, BC, Canada- Alıntıyı
gizle -
- Alıntıyı göster -
I'm trying to show that
â?«f dlambda<epsilon
A
State the problem precisely.
.
- Follow-Ups:
- Re: lebesgue
- From: v_aylin2000
- Re: lebesgue
- References:
- lebesgue
- From: v_aylin2000
- Re: lebesgue
- From: Robert Israel
- Re: lebesgue
- From: v_aylin2000
- lebesgue
- Prev by Date: Re: New symbolic/numeric/dynamic/intuitive programming language
- Next by Date: Re: Circle center from point on circle
- Previous by thread: Re: lebesgue
- Next by thread: Re: lebesgue
- Index(es):
Relevant Pages
|
