Infinite tetration giving - I*Omega costant=- I*0.567143...

Please could You check analytically or numerically if this derivation
is valid?

h(((e^(pi/2))^(1/Omega))*(e^I)) =-W((-pi/(2*Omega)-I))/(-pi/(2*Omega)-
I)=(-Omega+(I*(pi/2))/(-pi/(2*Omega)-I)= -Omega*I=-I*0,56714329..

The other branch of W should give +I*Omega?

The argument for h is complex, a product of:

e^(pi/(2*Omega))= e^(pi/2*0.567143..) = e^2,769663952
=15,95327204..

And e^I = cos1+I*sin1= 0,540302306+I*0,841470985

So numerically h( 8,619589667+I*13,42421553)= -I*0,56714329

Real counterpart of this is simpler:

h(Omega^(1/Omega))=h(1/e) = -W(-ln(1/e)/(-ln(1/e))= -W(1)/1=-
Omega=-0,56714329

Square superroot of (Omega^1/Omega) :

ssrt(Omega^(1/Omega) = ln(1/e)/W(ln(1/e))= -1/W(-1)= -1/
(-0.318131505204764 + 1.337235701430689*I) =
0.16837688705553+0.707755195958823*I.

Thank You in advance,

Ivars
.