Re: MinimalPolynomial

KY <wkfkh056@xxxxxxxxxxx> writes:

Prove that Cos[tdegree] is algebraic.

MinimalPolynomial of Cos[tDegree].

( t element of {1, 2, 3, 4, 5, 6, 7, 8, 9, 10})

Hint: cos(n theta) = T_n(cos(theta)) where T_n is the
n'th Chebyshev polynomial of the first kind.
--
Robert Israel israel@xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.