Re: Cardnality of integers > Cardnality of integers

On Mar 20, 6:47 pm, Tim Little <t...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
On 2008-03-20, S_Pa...@xxxxxxxxxxx <S_Pa...@xxxxxxxxxxx> wrote:

Now, suppose Cantor tried to convince me that:
RN * 2^k1 * 3k^2 * 5k^3... is not on this plane with a diagonal
argument involving a sequence of steps:

The definition of the diagonal does not involve a "sequence of steps",
any more than defining f:N->N by f(n) = n^2 involves an infinite
sequence of steps.

A sequence is simply a function with natural numbers as the domain.
The entries in your list are sequences that can be mapped to
rationals.  Diagonalization gives you a sequence, but you would then
need to prove that it corresponds to a rational.

Induction will not suffice.  It only proves properties of every
*finite* subsequence.

Thus the rationals have a 'distribution since they can be mapped to
the plane.

The rationals have uncountably many distributions.  None of them are
uniform.

Yes, you can consider the limit of probabilities over some sequence of
finite uniform distributions.  It would be a grave mistake to assume
that the limit is a probability in some distribution itself, though.
If you choose a different sequence of finite uniform distributions,
you can get a different limit.

- Tim

Consider concentric circles all centered about the orgin with radius 1/
zeta(n).
No draw an ulam spiral with very tiny squares.
Euler proved that in both cases those concentric circles stay in the
same place.
.

Relevant Pages

  • Re: Cardnality of integers > Cardnality of integers
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